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My question:

eH1gG9.png

Part a) is do-able, but I can't get Part b)?

The first integral, if u solve, gives you arctana-arctan1+c

The second integral gives u arctan1-arctana^-1

as they are equal, by moving artana^-1 to the left and arttan1 to the right you have the thing they ask.

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These are some of the questions I am not sure of.... (I have no idea how to upload a word document in this forum....)

As I am taking further math I integrated 4 options topics.....

I really need your help.... skype me if necessary :grassrootzcj

Edited by Grassroot
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Can anyone explain how to graph y=2x+cos2x ? without a graphing calculator. This was on the May 2011 P1 exam...

I know, this was a difficult question!

I think, I'm not sure though, you have to graph y=2x first.

And use that line to draw cos(2x) over it.

In other words, consider that line to be the equilibrium line (as if the graph paper is rotated a bit)

This picture explains more,

WolframAlpha--y_2x__y_cos_2x___y_2x_cos_2x___Plot__2012_04_22_0418.gif

So its like rotating the graph of cos(2x) to be over the graph of 2x

But again, I'm not sure, because the amplitude and the period does not look the same to me!

Lets see what others say ...

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Any idea how to do part b)ii)?

B3Ug8K.png

think that two friends as one...

you will have 2×10×9×8×7

and the word any two indicates to pick 2 from 5, we have 2C5=60

so it should be 120×10×9×8×7

but if the two friends were to sit next to Alice, Alice only has 8 choices of seats as she cannot sit on the leftmost/rightmost seats.

and there are 6 ppl including Alice.

so should be 8*2*1*7*6*5*(5C2)..... answer is 33600

Edited by Desy Glau
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