dessskris Posted August 27, 2011 Report Share Posted August 27, 2011 Hint:x(a+d)+y(a+2d)=a+3d orx(a+d)+y(a+2d)+z(a+3d)=a+4dbetter to doax + (a+d)y = a + 2dless terms...You will see the significance later once you solve the question. (on your x and y... WHAT'S LEFT?)Erm.. I feel stupid for asking this, but how did you get this answer? What chapter is this from?haha... no chapter. you only notice there are common differences and then you come up with the aforementioned form. Reply Link to post Share on other sites More sharing options...
alramsey Posted August 29, 2011 Report Share Posted August 29, 2011 are we actually supposed to write a second draft for this IA type? because my teacher said he'll be going through it and it's been ages and he didn't even mention about the IA so i'm starting to think the thing i've submitted will be the final............... Reply Link to post Share on other sites More sharing options...
caveat emptor Posted August 29, 2011 Report Share Posted August 29, 2011 its just surprising why more than half of the world chose to do type 2, patterns of complex numbers, and am like some of the few that is doing the shadow functions! :/ does anyone of a forum that discusses about shadow functions or should i start one? Reply Link to post Share on other sites More sharing options...
dessskris Posted August 29, 2011 Report Share Posted August 29, 2011 are we actually supposed to write a second draft for this IA type? because my teacher said he'll be going through it and it's been ages and he didn't even mention about the IA so i'm starting to think the thing i've submitted will be the final............... I'm not very sure... try to ask your teacher? its just surprising why more than half of the world chose to do type 2, patterns of complex numbers, and am like some of the few that is doing the shadow functions! :/ does anyone of a forum that discusses about shadow functions or should i start one? patterns of complex numbers is type 1. and we don't get to choose. our teachers chose. it exists already http://www.ibsurvival.com/topic/15514-shadow-functions/ Reply Link to post Share on other sites More sharing options...
caveat emptor Posted August 29, 2011 Report Share Posted August 29, 2011 patterns of complex numbers is type 1. and we don't get to choose. our teachers chose.it exists already http://www.ibsurvival.com/topic/15514-shadow-functions/wow! my teacher stated that we could choose any type we want for the portfolio, as long as you do atleast one. Reply Link to post Share on other sites More sharing options...
dessskris Posted August 31, 2011 Report Share Posted August 31, 2011 wow! my teacher stated that we could choose any type we want for the portfolio, as long as you do atleast one.actually you have to do two. one from type 1 and another one from type 2.you're so lucky. I wish I could choose too, I'd choose patterns in complex numbers and modelling a functional building. sigh. Reply Link to post Share on other sites More sharing options...
Guest ...^.... Posted September 6, 2011 Report Share Posted September 6, 2011 hello everyone... I am stuck in Part A last point.... Proving your conjecture...My conjecture is that the solution will be the same which (-1,2) when they exhibit the same arithmetic pattern in their coefficient.I am not sure how they want me to prove it. Reply Link to post Share on other sites More sharing options...
dessskris Posted September 6, 2011 Report Share Posted September 6, 2011 yes it is correct.prove it by stating the general 2x2 linear system and then try to find the solution algebraically (just like what you did before) and then you'll get the same solution. Reply Link to post Share on other sites More sharing options...
Guest ...^.... Posted September 6, 2011 Report Share Posted September 6, 2011 Thank Desy. Found it But now I am stuck with the software I should use. I wanted to use Excel. But that would be tiring Do anyone know, or used any other efficient and useful software. any help is appreciated Reply Link to post Share on other sites More sharing options...
dessskris Posted September 6, 2011 Report Share Posted September 6, 2011 Autograph is the best. it can plot 3D graphs too (for second part of part A) and it can also generate you 100 lines automatically (useful for part B). Reply Link to post Share on other sites More sharing options...
Guest ...^.... Posted September 6, 2011 Report Share Posted September 6, 2011 Thank you very much, I was going to use Matlab or Maple to generate the equation then insert then in a graph. Reply Link to post Share on other sites More sharing options...
Guest ...^.... Posted September 7, 2011 Report Share Posted September 7, 2011 Anybody who is alive could help me!!! I did a horrible mistake. My proof is not good and it is not a proof. I am stuck with it. My portfolio is due to 3 days . Someone HELP!!!! Reply Link to post Share on other sites More sharing options...
MR.AHM Posted September 7, 2011 Report Share Posted September 7, 2011 Anybody who is alive could help me!!! I did a horrible mistake. My proof is not good and it is not a proof. I am stuck with it. My portfolio is due to 3 days . Someone HELP!!!! Hi, You mean the proof for the arithmetic progression. I did only some notes on this IA, so I don’t think if I can help you that much. But can you give your general formula for the arithmetic progression of the coefficient in the linear equation. Just to make sure you are in the right track. Reply Link to post Share on other sites More sharing options...
Guest ...^.... Posted September 7, 2011 Report Share Posted September 7, 2011 What are you talking about? What General formula? I only wrote a statement that shows there is an arithmetic progression. Reply Link to post Share on other sites More sharing options...
MR.AHM Posted September 7, 2011 Report Share Posted September 7, 2011 What are you talking about? What General formula? I only wrote a statement that shows there is an arithmetic progression.Now, I know why you couldn’t prove it, because you didn’t have the general formula. Well, let say ax + by = ca is the starting coefficient of the arithmetic progression b is the second one which will be a + kc is the last one and it will be a + k + k, which is actually a+2KNow use these to make the formula. And then I think you will be able to find the proof easily Reply Link to post Share on other sites More sharing options...
Guest ...^.... Posted September 7, 2011 Report Share Posted September 7, 2011 Okay, I tried to do it, and here is what I gotax + (a+k)y = a + 2kBut now I am still stuck again. I can’t find anything. Can you please elaborate? Thank you Reply Link to post Share on other sites More sharing options...
MR.AHM Posted September 7, 2011 Report Share Posted September 7, 2011 Okay, I tried to do it, and here is what I gotax + (a+k)y = a + 2kBut now I am still stuck again. I can’t find anything. Can you please elaborate? Thank youI can’t help you that much into details. But I think here is a big hint. Use substitution now (-1,2).You should get what on the Left Hand Side = the Right Hand Side And this will be your proof, it’s like 1+1=2 The LHS=RHS so it is true. You should find the same thing when you use substitution. Reply Link to post Share on other sites More sharing options...
dessskris Posted September 8, 2011 Report Share Posted September 8, 2011 urgh... that is not proving.you have 2 equations in all your examples right? so when generalising, you also need 2 equations. use different parameters. then just solve them algebraically the way you did with your example. in the end you can cancel the parameters off and get the same solution as in your examples. Reply Link to post Share on other sites More sharing options...
MR.AHM Posted September 8, 2011 Report Share Posted September 8, 2011 urgh... that is not proving. you have 2 equations in all your examples right? so when generalising, you also need 2 equations. use different parameters. then just solve them algebraically the way you did with your example. in the end you can cancel the parameters off and get the same solution as in your examples. It is a proof, but not elegant. I have an elegant proof, but I can't help him with that because I gave him a lot of help. He didn't seem to understand what I wanted him to do. So I made him do this one. I made him insert the point of intersection in that equation to get the proof. I know that this proof only worked because he knew the intersection point. However, the proof I have doesn't require you to know the intersection point in the first place. However, I don't think he was able to figure it out by himself "better than nothing" I didn't do any cancelling, but what I did is some rearranging to that equation and extracted the proof that it will work for any n×n. Maybe you got another proof, but mine is hundered percent correct. And I am sure of that. and I can send you a message of the proof if you want to Reply Link to post Share on other sites More sharing options...
dessskris Posted September 8, 2011 Report Share Posted September 8, 2011 (edited) please just stop bragging and help people whenever you want. if you don't want to help just ignore them.there's never "I can't help him with that because I gave him a lot of help" for me. Edited September 8, 2011 by Desy Glau Reply Link to post Share on other sites More sharing options...
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