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How to solve this matrix?


Laura27

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They give me two matrices:

Matrix C = (a= -2)(b=4) (c=1)(d=7)

Matrix D = (a=5) (b=2) (c=-1) (d= x)

Instructions are: "Matrix Q is such that 3Q = 2C - D", FIND Q

If there is a matrix with "x", and no matrix as D

how do I solve this??

Edited by Laura27
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Right now I am not able to...anyway they just give those instructions and no extra information.

Well, only "The matrix 2×2Q is such that 3Q=2C-D" and both matrix (C and D)

But I do not think that "2 × 2Q" changes something, or it does?

(By 2×2 they concern to the size/dimension of the matrix)

Edited by Laura27
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  • 3 weeks later...

Assuming they want us to find Q in terms of both nrs and x´s, then

3Q=2C-D

Where C and D are given in the first post

we say that 2C-D=P

So 3Q=P

P=(a=-9, b=6, c=1 and d=14-x) by 2C-D

Q=1/3*P so Q=(a=-3, b=2, c=1 and d=((14-x)/3)

Note that I assumed that x is to be x and not any other nr because our math teacher showed us a matrix question from an old exam whose answer was given like that, and it did not say anything about giving the answer in terms of x in that question.

Hope this helps

Edited by mhmd123
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