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Integration


fan

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f(x) = x4(x+1)4(2x+1) = (x(x+1))4(2x+1)

u = x(x+1)

du/dx = 2x+1

dx = du/(2x+1)

Note: I'll use || as the integral sign

|| f(x) dx = || x(x+1))4(2x+1) dx = || u4(2x+1) du/(2x+1) = || u4 du = u5/5 + c = 1/5*x5(x+1)5 + c

For substitution, it is advised, probably a must, to substitute the function inside a function. In this case my first attempt was u = x+1, since the outside function was "power 4". It didn't work. "Extract/Remove/Combine the powers" and the inside function becomes x(x+1). Using u = x(x+1) solves it!

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