Ossih Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy. Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 How did you define the wave function ? Reply Link to post Share on other sites More sharing options...
Ossih Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle How did you define the wave function ? Yeah I wrote the work done in one cycle But I feel the IB might be picky and require the word net that you put :/ I defined a wavefunction as a function whose amplitude squared gives you the probability of finding an electron at that point. From past papers, its enough to say thats a wavefunction that's associated with the position of an electron I think :$ Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 You know first I wrote that the change in u was - 210 , but fortunately when I was revising I corrected it, and for the mass in q7, I divided by the frequency instead of multiplying by it, I knew my formulae well but this caught me.And for showing that they have the same mass I said that k is same since springs are identical and w is constant but failed to say that it is constant because period for A and B is the same For the continuous loop I imagined that it is a circle so that the circumference will increase .....How did you calculate the angular separation /theta in q4 ? Reply Link to post Share on other sites More sharing options...
whydidiprocrastinate Posted May 10, 2015 Report Share Posted May 10, 2015 Anyone do the question on digital technology? What did they get for the play time on the DVD? I got 59 minutes, but I'm not sure if that's correct. Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle How did you define the wave function ? Yeah I wrote the work done in one cycle But I feel the IB might be picky and require the word net that you put :/ I defined a wavefunction as a function whose amplitude squared gives you the probability of finding an electron at that point. From past papers, its enough to say thats a wavefunction that's associated with the position of an electron I think :$I've never seen in past papers a definition for wave function , for this reason I was doubting my answer, the could rather be describe what is meant by a wave function,mbecause the answer it self is not a definition for wavefunction, it Is like you define mv^2 s2 and you say it is energy due to the movement of the body, but no, it is the formula used to....Anyone do the question on digital technology? What did they get for the play time on the DVD? I got 59 minutes, but I'm not sure if that's correct.Someone did it and got your double, 118 Reply Link to post Share on other sites More sharing options...
Sofia. Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle I just said it cannot perform useful work since in a cyclic process energy is always degraded, which felt a bit too easy. I wrote that too, although I think I might have put it in terms of total work done by the system. Struggling to remember if I put minimum energy in for BE, btw. So annoying! Hopefully I did. Reply Link to post Share on other sites More sharing options...
Sofia. Posted May 10, 2015 Report Share Posted May 10, 2015 You know first I wrote that the change in u was - 210 , but fortunately when I was revising I corrected it, and for the mass in q7, I divided by the frequency instead of multiplying by it, I knew my formulae well but this caught me.And for showing that they have the same mass I said that k is same since springs are identical and w is constant but failed to say that it is constant because period for A and B is the same For the continuous loop I imagined that it is a circle so that the circumference will increase .....How did you calculate the angular separation /theta in q4 ? Continuous loop, which question was that? The emf one, on Section A? That was because of the current that would flow. Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle I just said it cannot perform useful work since in a cyclic process energy is always degraded, which felt a bit too easy. I wrote that too, although I think I might have put it in terms of total work done by the system. Struggling to remember if I put minimum energy in for BE, btw. So annoying! Hopefully I did.Sofiathis time I used the alternative edefinition, which is energy released when a nucleus is assembled form its nucleons/ individual constituentsYou know first I wrote that the change in u was - 210 , but fortunately when I was revising I corrected it, and for the mass in q7, I divided by the frequency instead of multiplying by it, I knew my formulae well but this caught me.And for showing that they have the same mass I said that k is same since springs are identical and w is constant but failed to say that it is constant because period for A and B is the same For the continuous loop I imagined that it is a circle so that the circumference will increase .....How did you calculate the angular separation /theta in q4 ? Continuous loop, which question was that? The emf one, on Section A? That was because of the current that would flow.Yes I like your answer, and don't know why you didn't solve 9, it seems that that you have a good understanding for electricity Reply Link to post Share on other sites More sharing options...
whydidiprocrastinate Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle How did you define the wave function ? Yeah I wrote the work done in one cycle But I feel the IB might be picky and require the word net that you put :/ I defined a wavefunction as a function whose amplitude squared gives you the probability of finding an electron at that point. From past papers, its enough to say thats a wavefunction that's associated with the position of an electron I think :$I've never seen in past papers a definition for wave function , for this reason I was doubting my answer, the could rather be describe what is meant by a wave function,mbecause the answer it self is not a definition for wavefunction, it Is like you define mv^2 s2 and you say it is energy due to the movement of the body, but no, it is the formula used to....Anyone do the question on digital technology? What did they get for the play time on the DVD? I got 59 minutes, but I'm not sure if that's correct.Someone did it and got your double, 118 Looks like it's time to pray for a 5 Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 Sofia how did you prove in q7 that goths masses are the sameOssih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle How did you define the wave function ? Yeah I wrote the work done in one cycle But I feel the IB might be picky and require the word net that you put :/ I defined a wavefunction as a function whose amplitude squared gives you the probability of finding an electron at that point. From past papers, its enough to say thats a wavefunction that's associated with the position of an electron I think :$I've never seen in past papers a definition for wave function , for this reason I was doubting my answer, the could rather be describe what is meant by a wave function,mbecause the answer it self is not a definition for wavefunction, it Is like you define mv^2 s2 and you say it is energy due to the movement of the body, but no, it is the formula used to....Anyone do the question on digital technology? What did they get for the play time on the DVD? I got 59 minutes, but I'm not sure if that's correct.Someone did it and got your double, 118Looks like it's time to pray for a 5 Just do your best on paper 3 Reply Link to post Share on other sites More sharing options...
Vioh Posted May 10, 2015 Report Share Posted May 10, 2015 no but that's what im saying, its not the case of 10 electrons passing through that ammeter in 0.5s. Each individual electron is faster BUT the time after which each electron whizzes off is the same, because there's a one-to-one instantaneous correspondence between a photon hitting and an electron hitting. What I'm saying is that initially, each of those 10 electrons travelled at say 1m/s and travelled say 12m of wire. Each electron was shot with a delay of 1s in between them. Now, those same electrons are travelling at 2m/s, still travelling 12m of wire, still a 1s delay between them. Just the shots are faster, but the overall movement of charge isn't faster itself! Do you get what I'm trying to say haha. I can't think of a good analogy. It's a matter of firing faster bullets and slower bullets, but the time interval between bullets is the same, so overall, the number of bullets per unit time is the same. Alright, let's consider that situation that you've set up. But i'll fix it a bit to fit my diagrams. So we will suppose that we will fire 6 electrons at 1m/s through a 4-meter wire, with a 1s delay between each electron. This can be represented by this diagram: Notice that the electrons are meant to be positioned just a bit before their respective positions. In other words, for t = 0 at p2, the electron e3 is a bit before that position p2.So from the diagram, during 1s-interval, only e3 has passed through p2, which means that the current is 1 electron charge per second (or 1e Amps). Let's now increase the speed by 2, we'll get the diagram: In this diagram, during 1s-interval, both e3 & e4 have passed through p2, which means that the current is 2 electron charge per second (or 2e Amps).So whatever situation you set up, when you increase kinetic energy (i.e. speed) of the electrons, the current will increase Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 (edited) Sofia and Ossih, I strongly feel that tomorrow they will get a question on Olber's paradox and the parallax method, and Take care of the definition like comet is icy/rocky body orbiting the sun in highly elliptical orbit, asteroid-minor planet between the orbits of Mars and Jupiter , take care of the order of planets from the sun, and order of their sizes, the class Oh Be A Fine Girl/Guy Kiss Me, look for this I simply the temperatures,Just memorize the the lower limit except for the first oneAnd add *100 to the numbersO. 280 -500B 99-280. A-74-99F-60-74G-49-60K-35-49M-20-35And for the colors it is very simple : You start with a couloir alone, the next stage is that coulour and another, than this 2nd color alone and so onSo blueBlue whiteWhiteYellow whiteYellow OrangeOrange red Edited May 10, 2015 by Hassan76 Reply Link to post Share on other sites More sharing options...
Sofia. Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle I just said it cannot perform useful work since in a cyclic process energy is always degraded, which felt a bit too easy. I wrote that too, although I think I might have put it in terms of total work done by the system. Struggling to remember if I put minimum energy in for BE, btw. So annoying! Hopefully I did.Sofiathis time I used the alternative edefinition, which is energy released when a nucleus is assembled form its nucleons/ individual constituents You know first I wrote that the change in u was - 210 , but fortunately when I was revising I corrected it, and for the mass in q7, I divided by the frequency instead of multiplying by it, I knew my formulae well but this caught me.And for showing that they have the same mass I said that k is same since springs are identical and w is constant but failed to say that it is constant because period for A and B is the same For the continuous loop I imagined that it is a circle so that the circumference will increase .....How did you calculate the angular separation /theta in q4 ? Continuous loop, which question was that? The emf one, on Section A? That was because of the current that would flow.Yes I like your answer, and don't know why you didn't solve 9, it seems that that you have a good understanding for electricity No, I hate electricity haha! Sheer luck, I think. I'd seen a similar question somewhere. Reply Link to post Share on other sites More sharing options...
Sofia. Posted May 10, 2015 Report Share Posted May 10, 2015 Sofia and Ossih, I strongly feel that tomorrow they will get a question on Olber's paradox and the parallax method, and Take care of the definition like comet is icy/rocky body orbiting the sun in highly elliptical orbit, asteroid-minor planet between the orbits of Mars and Venus , take care of the order of planets from the sun, and order of their sizes, the class Oh Be A Fine Girl/Guy Kiss Me, look for this I simply the temperatures,Just memorize the the lower limit except for the first oneAnd add *100 to the numbersO. 280 -500B 99-280.A-74-99F-60-74G-49-60K-35-49M-20-35And for the colors it is very simple :You start with a couloir alone, the next stage is that coulour and another, than this 2nd color alone and so onSo blueBlue whiteWhiteYellow whiteYellowOrangeOrange red Love Olber's paradox, hoping that will come. The asteroid belt is between Mars and Jupiter, right? Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 Ossih what temperature did you get for the thermodynamics question in q7, and the efficiency was 47% right, and what did you answer for the degraded energy? 500K And yeah the efficiency was 47%! I answered that the energy that is given off to surroundings is dissipated as kinetic energy in the molecules i.e. no more useful to do work, so it is degraded energy.You all got 500, I got 5000 and double checked my answer And I said that it is dissipated in the surroundings and transferred to it and no longer able to perform useful work and cannot flow into the system/gas from the surroundingsAnd what did you write for the area,mInwrote net work done by the gas during one compete cycle I just said it cannot perform useful work since in a cyclic process energy is always degraded, which felt a bit too easy. I wrote that too, although I think I might have put it in terms of total work done by the system. Struggling to remember if I put minimum energy in for BE, btw. So annoying! Hopefully I did.Sofiathis time I used the alternative edefinition, which is energy released when a nucleus is assembled form its nucleons/ individual constituentsYou know first I wrote that the change in u was - 210 , but fortunately when I was revising I corrected it, and for the mass in q7, I divided by the frequency instead of multiplying by it, I knew my formulae well but this caught me.And for showing that they have the same mass I said that k is same since springs are identical and w is constant but failed to say that it is constant because period for A and B is the same For the continuous loop I imagined that it is a circle so that the circumference will increase .....How did you calculate the angular separation /theta in q4 ? Continuous loop, which question was that? The emf one, on Section A? That was because of the current that would flow.Yes I like your answer, and don't know why you didn't solve 9, it seems that that you have a good understanding for electricity No, I hate electricity haha! Sheer luck, I think. I'd seen a similar question somewhere.I've also and very recently, in m12 hp2 tz1 q5 but they told us before it to state lenz law,You know, it is because in physics I don't like to write an answer I don't understand or not convinced withBtw Inlooked at Q 6 but didn't answer it, what did you answer for the question asking for the change in speed or energy of the speed Ships? Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 Sofia and Ossih, I strongly feel that tomorrow they will get a question on Olber's paradox and the parallax method, and Take care of the definition like comet is icy/rocky body orbiting the sun in highly elliptical orbit, asteroid-minor planet between the orbits of Mars and Jupiter, take care of the order of planets from the sun, and order of their sizes, the class Oh Be A Fine Girl/Guy Kiss Me, look for this I simply the temperatures,Just memorize the the lower limit except for the first oneAnd add *100 to the numbersO. 280 -500B 99-280.A-74-99F-60-74G-49-60K-35-49M-20-35And for the colors it is very simple :You start with a couloir alone, the next stage is that coulour and another, than this 2nd color alone and so onSo blueBlue whiteWhiteYellow whiteYellowOrangeOrange red Love Olber's paradox, hoping that will come. The asteroid belt is between Mars and Jupiter, right?Yes ur right sorry I'll correct it Reply Link to post Share on other sites More sharing options...
Sofia. Posted May 10, 2015 Report Share Posted May 10, 2015 Don't think there was such a question? There was one with the gravitational field strength, which turned out to be the acceleration. Reply Link to post Share on other sites More sharing options...
Hassan76 Posted May 10, 2015 Report Share Posted May 10, 2015 (edited) Don't think there was such a question? There was one with the gravitational field strength, which turned out to be the acceleration.It was after the mention of the change in speedSofia do you have all past papers, I mean do you want some or do you have them all, and you guys, does anyone need any past paper? Edited May 10, 2015 by Hassan76 Reply Link to post Share on other sites More sharing options...
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