kpatel27 Posted October 19, 2014 Report Share Posted October 19, 2014 How do you do 4^ log base 2 of 6 ? I would like the full explanation thanks! Reply Link to post Share on other sites More sharing options...
Vioh Posted October 19, 2014 Report Share Posted October 19, 2014 Here you go: Reply Link to post Share on other sites More sharing options...
Ossih Posted October 19, 2014 Report Share Posted October 19, 2014 The above answer is right, but in most cases, you're expected to do that without a calculator. So, you would do this: 4^(log2 6) = (2^2)^(log2 6) = 2^(2*log2 6) = 2^(log2 36) = 36 3 Reply Link to post Share on other sites More sharing options...
kpatel27 Posted October 19, 2014 Author Report Share Posted October 19, 2014 Thank you! Reply Link to post Share on other sites More sharing options...
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