saunders is god Posted October 31, 2010 Report Share Posted October 31, 2010 (edited) Hey guys, could anyone please do this question for me with workingWrite 2cos x - 5 sin x in the form kcos (x+b) k>0 0<b<2pithanks... Edited October 31, 2010 by saunders is god Link to post Share on other sites More sharing options...
dessskris Posted October 31, 2010 Report Share Posted October 31, 2010 2 cos x - 5 sin x = k cos (x+b)2 cos x - 5 sin x = k (cos x.cos b - sin x.sin b)2 cos x - 5 sin x = k cos b.cos x - k sin b.sin xCompare the coefficient of sin x- 5 = - k sin b5 = k sin bCompare the coefficient of cos x2 = k cos bDo substitution to solve for k and b. Find the values by yourself ok EDIT: I made a mistake above, re-check my working please. thanks Link to post Share on other sites More sharing options...
dessskris Posted October 31, 2010 Report Share Posted October 31, 2010 Automatic generated messageThis topic has been closed by a moderator.Reason: problem solved If you disagree with this action, please report this post, and a moderator or administrator will review it.Kind regards,IB Survival Staff Link to post Share on other sites More sharing options...
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