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Acids And Bases Question


tdubthebassist

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Wouldn't it be choice B? NaCl in water is just salt water -- no pH change. Na2CO3 will dissociate into Na(+) and CO3(2-)... and carbonate is a Bronsted-Lowry base when dissolved in water because it accepts a proton to become bicarbonate, right?

Both C and D have ammonium ions, which will donate protons.

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for questions like these, you should try to write the equations for the ions in solution:

A. NaCl, this would have the following equation with water molecule:

NaCl + H2O --> NaOH + HCl

the neutral solution that will result from adding NaCl to water is due to the neutralisation of NaOH with HCl. thus, pH would be 7 exactly.

B. Na2CO3, the equation for this one:

Na2CO3 + 2H2O --> 2NaOH + H2CO3

H2CO3 is a weak acid, while NaOH is a strong base, thus, the overall pH would be above 7.

C. NH4Cl:

NH4Cl + H2O --> HCl + NH3 + H2O

HCl is a strong acid, while NH3 is a weak base, thus, the overall pH is less than7.

D. NH4NO3:

NH4NO3 + H2O --> HNO3 + NH3 + H2O

HNO3 is a strong acid, while NH3 is a weak base, thus the overall pH is less than 7.

now that everything is clear, it's easy to spot that the Na2CO3 would produce a solution with the higher pH, since it's most basic.

note, though, that, technically speaking, the equations above are wrong, a salt does not react with water, it only forms ions. but you can use this method to help you decide which salt will ionize into the highest/ lowest solution.

good luck, hope you got it.

Edited by x___x
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