Jump to content

HL Integral Question

Recommended Posts

I think this is for an IA, so I won't go into too much details. If you know all the constants (and ω > 0) then this should be just integration by parts twice. It gets tricky if you have to plug in boundary conditions or initial conditions (ie from solving a differential equation) but likely you can just do that after. When I encountered something similar we had an infinite series instead of an indefinite integral but that trick will not work here. Basically for an infinite series you have to use some integral that equals to the Kronecker delta, such as a7OcAMx.png

  • Like 1
Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

  • Create New...