Melissi Posted April 13, 2014 Report Share Posted April 13, 2014 Okay, I might be completely stupid for asking this, but I'm having a blank.Could anyone explain the following point to me:squareroot(m^2) = |m|Please? m is just any real number, it doesn't specify whether it's positive or negative, and since (-m)^2 is the same as m^2 I'm a bit confused.A minor detail, I know, and I feel a bit silly for asking, but it would really help me understand this proof I'm doing if someone could help me out! Thanks! Reply Link to post Share on other sites More sharing options...
Bude Posted April 13, 2014 Report Share Posted April 13, 2014 (edited) Well if you want to find the modulus, you square root the sum of the components squared, and if you only have one component, that's it..? Edited April 13, 2014 by Bude Reply Link to post Share on other sites More sharing options...
elaifyanre Posted April 13, 2014 Report Share Posted April 13, 2014 (edited) For example Edited April 13, 2014 by ssy 2 Reply Link to post Share on other sites More sharing options...
Melissi Posted April 14, 2014 Author Report Share Posted April 14, 2014 Oh. Thanks so much! :'DI thought it was going to be an easy answer but I was having such a mental block... Oops? :') Reply Link to post Share on other sites More sharing options...
fufufuufufufufuuu Posted April 20, 2014 Report Share Posted April 20, 2014 Oh. Thanks so much! :'DI thought it was going to be an easy answer but I was having such a mental block... Oops? :')where did u get this question? Reply Link to post Share on other sites More sharing options...
Melissi Posted April 21, 2014 Author Report Share Posted April 21, 2014 Oh. Thanks so much! :'DI thought it was going to be an easy answer but I was having such a mental block... Oops? :')where did u get this question?In the "Mathematics Higher Level for the IB Diploma" textbook, by Fannon, Kadelburg, Woolley and Ward - I was working through the chapter on further trigonometry and they used it to prove some sort of identity, I can't remember which! Reply Link to post Share on other sites More sharing options...
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