(Sarcasm) Posted April 9, 2013 Report Share Posted April 9, 2013 I'm not sure if this is the right forum but I can't find any tutorial that involves these: how do I go about simplifying expressions like this:7^m+1 - 7^m all over 7^n - 7^n+2or5^2n+1 + 25^n all over 5^2n + 5^1+nalsox - 2^1/2 + 1)^1/2 X (x+1)/ root x -:what does that last bit even mean? ^For reference, these are in the Higher level maths core book chapter 7: Ex 7.1 Q8 d-f on page 215 Reply Link to post Share on other sites More sharing options...
cricketcrazynerd Posted April 9, 2013 Report Share Posted April 9, 2013 (edited) Is this what you mean:(7^m+1) - (7^m) ------------------- (7^n) - (7^n+2)= 7^m (7-1) -------------- 7^n (1-7^2)= 7^m (6) ----------- 7^n (-48)= 7^m -------- 7^n (-8)= 7^m x 7^n x (-8)^-1I guess that's simplified...Just remember to take the common factor out of the bracket at the beginning Edited April 10, 2013 by cricketcrazynerd 1 Reply Link to post Share on other sites More sharing options...
(Sarcasm) Posted April 9, 2013 Author Report Share Posted April 9, 2013 (edited) yes that is the right answer! I'm not sure I understand what you've done in your first step though, which are the common factors?EDIT: got that, Thanks!! but what is going on in the fourth step?is it the same principle for the other question? Edited April 9, 2013 by (Sarcasm) Reply Link to post Share on other sites More sharing options...
Rahul Posted April 10, 2013 Report Share Posted April 10, 2013 I believe he made a typo - it should be /8. He's just cancelling the factor of 6 out. Reply Link to post Share on other sites More sharing options...
cricketcrazynerd Posted April 10, 2013 Report Share Posted April 10, 2013 yes that is the right answer! I'm not sure I understand what you've done in your first step though, which are the common factors?EDIT: got that, Thanks!! but what is going on in the fourth step?is it the same principle for the other question?1) 7^m is a common factor of both 7^m and 7^m+1 (this is 7^m + 7^1 remember?_4) it's a typo, it's meant to be -8 (soz!)I believe he made a typo - it should be /8. He's just cancelling the factor of 6 out.I'm not exactly fond of being referred to as a male or HE...Simranyes that is the right answer! I'm not sure I understand what you've done in your first step though, which are the common factors?EDIT: got that, Thanks!! but what is going on in the fourth step?is it the same principle for the other question?1) 7^m is a common factor of both 7^m and 7^m+1 (this is 7^m + 7^1 remember?_4) it's a typo, it's meant to be -8 (soz!)I believe he made a typo - it should be /8. He's just cancelling the factor of 6 out.I'm not exactly fond of being referred to as a male or HE... is it the same principle for the other question?Yep... just take out a common factorSimran 1 Reply Link to post Share on other sites More sharing options...
Rahul Posted April 10, 2013 Report Share Posted April 10, 2013 Sorry, my apologies. I should have double checked your profile first :/ 1 Reply Link to post Share on other sites More sharing options...
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