toribaldwin17 Posted May 21, 2012 Report Share Posted May 21, 2012 Okay so here is the problem: (ax2+ b/x )8= 256x16+4096x13+...+kx+... a. Find a (which I found to be 2) b. Find b (which I found to be 4) c. Find k As you can already tell, I don't know how to find k AT ALL! Lol please help me, I have a test tomorrow. Thank you! Reply Link to post Share on other sites More sharing options...
maxilius Posted May 21, 2012 Report Share Posted May 21, 2012 Hi there. Do you have skype? I'd be glad to help you If you have skype, add me: perry_feng I will give you step by step help. no worries. 1 Reply Link to post Share on other sites More sharing options...
kiwi.at.heart Posted May 21, 2012 Report Share Posted May 21, 2012 To get kx, you need the power of x on ax^2 to be 1 greater than b/x. This works when ax^2 is to the power of 3 and when b/x is to the power 5. Then you can just sub these into how you find the value of k: 8C3 (2x^2)^3 (4/x)^5 = 56*8x^6*1024/x^5 = 458752x so k = 458752 1 Reply Link to post Share on other sites More sharing options...
toribaldwin17 Posted May 23, 2012 Author Report Share Posted May 23, 2012 Thank you! I eventually worked it out like kiwi.at.heart. It didn't even appear on our final today! Shame Shame... Reply Link to post Share on other sites More sharing options...
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