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Matrices and Linear Systems


IBVeryStressed

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wow, took me a while to actually understand the question but now i get it. The basic idea is:

AA-1=I

therefore, if (I-X) is inverse of I+X+X2

then (I-X)(I+X-X2) = I <- this is what you want to show.

so:

(I-X)(I+X-X2)=I2+IX+IX2-XI-X2-X3

=
I+X+X
2
-X-X
2
-X
3

=
I-X
3

=
I
because
X
3
=
0
, given in question.

Now that, we've showed (I-X)(I+X-X2) = I, we're done. In the exam, all you'll have to show is what i wrote in the quote.

Edited by Gene-Peer
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