HJ:) Posted June 3, 2009 Report Share Posted June 3, 2009 (edited) Although I don't take chemistry, this question got me hooked.Calculate the molarity of an HCl solution if 25.0 mL of the solution is neutralized by 15.5 mL of 0.80 M NaOHI took this in IGCSE last year but forgot everything about it, and it is really frustrating can anyone help me solve this? I forgot all the steps!!Thank you Edited June 3, 2009 by HJ:) Reply Link to post Share on other sites More sharing options...
moneyfaery Posted June 3, 2009 Report Share Posted June 3, 2009 (edited) NaOHv = 0.0155Lc = 0.80mol/Ln = 0.80(0.0155) = 0.0124molHCLv = 0.025Lc = 0.0124/0.025 = 0.496mol/LHence 0.50mol/L to 2 sig digs. Edited June 3, 2009 by Irene Reply Link to post Share on other sites More sharing options...
Tilia Posted June 4, 2009 Report Share Posted June 4, 2009 One thing you need to do in chemistry is to memorize the formulae m=nM and c=n/V. P1 is impossible wihtout them. Reply Link to post Share on other sites More sharing options...
HJ:) Posted June 4, 2009 Author Report Share Posted June 4, 2009 One thing you need to do in chemistry is to memorize the formulae m=nM and c=n/V. P1 is impossible wihtout them. thank God I don't take chemistry, less formulas to memorize Reply Link to post Share on other sites More sharing options...
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