CalissaRelics Posted November 15, 2016 Report Share Posted November 15, 2016 (edited) Hi, Could someone please help me with this question: Which statement is correct about the electrolysis of molten PbI2 1) Chemical Energy is converted into electrical energy 2) Pb2+ ions are oxidized at the negative electrode (cathode) 3) I2 is produced at the positive electrode (anode) 4) Ions are produced at both electrodes Why is the answer 3) ????? Thanks Edited November 15, 2016 by CalissaRelics Reply Link to post Share on other sites More sharing options...
mack Posted November 15, 2016 Report Share Posted November 15, 2016 The anode is connected to the positive terminal of a power supply. Since electrons from from the negative to the positive terminal, electrons must flow out of the solution via the anode. Since the loss of electrons corresponds to an increase in oxidation state, oxidation must occur to the molten substance at the anode. The substance consists of Pb2+ ions and I- ions, as it is ionic. Of these two ions, the iodide is oxidised to produce electrons. When the ion gives up an electron, I- reverts to just iodine, which is presented as the species I2 (g). 2I- => I2 (g) + 2e- Thus 3) is correct. 1) is not correct as electrolysis converts electrical into chemical energy. 2) is incorrect as oxidation does not occur at the cathode, and lead ions are not oxidised. 4) Is also incorrect as ionisation does not occur at either electrode: iodine gas is produced at the anode, and lead metal at the cathode. 1 Reply Link to post Share on other sites More sharing options...
CalissaRelics Posted November 15, 2016 Author Report Share Posted November 15, 2016 Thank you so much!!! I understood where I went wrong now Reply Link to post Share on other sites More sharing options...
kw0573 Posted November 15, 2016 Report Share Posted November 15, 2016 It may be helpful to remember that in both voltaic and electrolytic cells, oxidation occurs at anode and reduction occurs at cathode. And in both cases, electron flow is in direction of negative end to the positive end. In voltaic cells, there is no external voltage and the end of that generates electrons (anode) is negative; electron consumption (cathode) is positive. In electrolytic cells, there is external voltage that first generates the positive and negative ends of the cell. Then generated electrons (anode) is at positive end because that's where electrons are attracted to; similarly electron consumption (cathode) is negative, where electrons are supplied. Reply Link to post Share on other sites More sharing options...
Msj Chem Posted November 16, 2016 Report Share Posted November 16, 2016 Maybe this video will help: Reply Link to post Share on other sites More sharing options...
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