Chem Kinetics question

[allthebest]

I don't quite understand how to find the rate constant when the information given is as follows:

 

	Composition by volume of mixture / cm3				Initial rate
Experiment	1.00 mol dm–3 CH3COCH3(aq)	Water	1.00 mol dm–3 H+(aq)	5.00 × 10–3 mol dm–3 I2 in KI	/ mol dm–3 s–1
1	10.0	60.0	10.0	20.0	4.96 × 10–6
2	10.0	50.0	10.0	30.0	5.04 × 10–6
3	5.0	65.0	10.0	20.0	2.47 × 10–6
4	10.0	65.0	5.0	20.0	2.51 × 10–6

 

I need the concentration, but there are variations of volumes in cm3. I don't know how those variation in volume will affect the concentration.

The rate equation is rate= k [CH3COCH3]^2 [H+]

Why is the concentration of CH3COCH3 and H+ 0.1?

other than that, I know how to get the answer. please explain why their concentrations are 0.1 and how variations in volume affect the concentrations!

Thank you very much!!

[kw0573]

1) Find total volume in each experiment. Assume volumes simply add together.
2) Use Cv = Cv to calculator concentration in the diluted reaction chamber. 

[allthebest]

On 2016. 8. 21. at 10:53 AM, kw0573 said:

1) Find total volume in each experiment. Assume volumes simply add together.
2) Use Cv = Cv to calculator concentration in the diluted reaction chamber. 

thank you!