Scienuk Posted August 5, 2016 Report Share Posted August 5, 2016 Can someone please explain the question and how you find the solution, the question and answer are below attached below: Thanks! Reply Link to post Share on other sites More sharing options...
kw0573 Posted August 5, 2016 Report Share Posted August 5, 2016 If you multiply the second reaction by 3, the 3/2 oxygens cancel out when you proceed to add the reactions. iron(III) oxide + 3 carbon monoxide ---> 2 solid iron + 3 carbon dioxide The Gibb's free energy of this reaction is (742)+(3)(-257) = -29 kJ, which because is negative, means reaction is spontaneous in the forward direction. Reply Link to post Share on other sites More sharing options...
Scienuk Posted August 5, 2016 Author Report Share Posted August 5, 2016 1 hour ago, kw0573 said: If you multiply the second reaction by 3, the 3/2 oxygens cancel out when you proceed to add the reactions. iron(III) oxide + 3 carbon monoxide ---> 2 solid iron + 3 carbon dioxide The Gibb's free energy of this reaction is (742)+(3)(-257) = -29 kJ, which because is negative, means reaction is spontaneous in the forward direction. Thank you! but why did you decide to cancel out the O2s from both reactions, any specific reason? Reply Link to post Share on other sites More sharing options...
kw0573 Posted August 5, 2016 Report Share Posted August 5, 2016 43 minutes ago, Scienuk said: Thank you! but why did you decide to cancel out the O2s from both reactions, any specific reason? So that we get one reaction whose reactants are iron(III) oxide and carbon monoxide, as specified in question. 1 Reply Link to post Share on other sites More sharing options...
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