Guest Posted January 28, 2016 Report Share Posted January 28, 2016 Hei.So I'm have trouble calculating the % yield for NH3 of: N2 + 3H2 = 2NH3 I know that you're supposed to find the limiting reagent, which is N2, and I know for sure that I got that right. The masses given for each molecule is 400 kg (N2), 200kg (2H2), and 220kg (2NH3). I know that you're supposed to do the (molar mass of NH3)/(220)) x 100, but I'm not getting the right answer. What am I doing wrong? The correct answer is 45.2% Reply Link to post Share on other sites More sharing options...
Guziec Posted January 28, 2016 Report Share Posted January 28, 2016 (edited) I tried to show everything as clearly as possible, if you still have some doubts send me a message Edited January 28, 2016 by Guziec 1 Reply Link to post Share on other sites More sharing options...
Guest Posted January 28, 2016 Report Share Posted January 28, 2016 I tried to show everything as clearly as possible, if you still have some doubts send me a message Hei! Thanks for trying to help. Unfortunately, I'm not qualified to download files yet. Is it alright if you could explain what I'm doing wrong instead? Thanks! Reply Link to post Share on other sites More sharing options...
King112 Posted January 28, 2016 Report Share Posted January 28, 2016 He hasn't posted it as a file.It is a picture. 1 Reply Link to post Share on other sites More sharing options...
Guziec Posted January 28, 2016 Report Share Posted January 28, 2016 He hasn't posted it as a file.It is a picture.Anyway, I also can't see it, I've just sent a PM Reply Link to post Share on other sites More sharing options...
Guest Posted January 28, 2016 Report Share Posted January 28, 2016 I tried to show everything as clearly as possible, if you still have some doubts send me a message image.jpgI had my chemistry exam today, and a similar question was on there about % yield. Thanks so much! Reply Link to post Share on other sites More sharing options...
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