Jump to content

Kinetics/Equilibrium


Guest

Recommended Posts

A mechanism is a schematic understanding of a complex, multi-step reaction by chunking it into simpler, often involving two reactants, reactions. The mechanism is presented in order of precedence. In this case, the slow step occurs before the two fast steps.

Recall what steps in a mechanism contributes to the rate law. 
Write the rate law.
For explanatory purposes, suppose the rate is proportional to

A*B^2*C^3*D^4

 

If you double the concentration for each species given in the choices, {or example for choice a) you only double A, for choice b) you double A and double C, and so on} which combination causes the greatest change in rate?

Just saying, you shouldn't eliminate any choices before you understood the question!

EDIT: some text-rendering issues. I meant concentration for any referals to A, B, C, D

Edited by kw0573
Link to post
Share on other sites

Ok, but in the first equation, there are 2 mols of A and C. So shouldn't the answer be B? Since increasing the concentration will affect the rate?

(the answer is A, by the way. I relaized that I hadn;t mentioned that.)

Edited by frank!e
Link to post
Share on other sites

For a non-equilibrium slow reaction, the rate is just the reactant side with the coefficients as the exponents

r = k * A^2
It's a bad question because it should be "substance(s)" in the question. And a, b, and e should be equally correct, because C and D do not contribute to the rate. However if you pick only b, that is not right because you hadn't gotten the right rate law. 

Edited by kw0573
Link to post
Share on other sites

It's a bad question because it should be "substance(s)" in the question. And a, b, and e should be equally correct, because C and D do not contribute to the rate. However if you pick only b, that is not right because you hadn't gotten the right rate law. 

 

Not really, because I think both C and D can contribute to the rate. In this case, they would slow down the reaction because C is the product of the first step of the reaction, and D is the product of the second step of the reaction. And by the Le Chartelier's principle, increasing the concentration of the products would shift the reactions to the left, thus slowing down the overall three-step reaction above. So I think only (a) should be the correct answer. Isn't that right?

Edited by Vioh
Link to post
Share on other sites

 

It's a bad question because it should be "substance(s)" in the question. And a, b, and e should be equally correct, because C and D do not contribute to the rate. However if you pick only b, that is not right because you hadn't gotten the right rate law. 

 

Not really, because I think both C and D can contribute to the rate. In this case, they would slow down the reaction because C is the product of the first step of the reaction, and D is the product of the second step of the reaction. And by the Le Chartelier's principle, increasing the concentration of the products would shift the reactions to the left, thus slowing down the overall three-step reaction above. So I think only (a) should be the correct answer. Isn't that right?

 

The slow step is not an equilibrium but it goes to completion. Le Chantelier's principle only works for shifting equilibrium position.

 

Regardless, the question can only say the slow step goes to completion, and not in equilibrium, WITH THE ASSUMPTION that the reverse reaction has no effect or is essentially not observable. We cannot break this assumption when looking at choices B and E.

  • Like 1
Link to post
Share on other sites

The slow step is not an equilibrium but it goes to completion. Le Chantelier's principle only works for shifting equilibrium position.

Regardless, the question can only say the slow step goes to completion, and not in equilibrium, WITH THE ASSUMPTION that the reverse reaction has no effect or is essentially not observable. We cannot break this assumption when looking at choices B and E.

 

yes, you're absolutely correct. I completely forgot that the equilibrium sign is not there in the equations. ugh... such a bad question!

Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...