Chemstryandbio Posted December 27, 2015 Report Share Posted December 27, 2015 Hi I know most of you are worried with EE and TOK but I would appreciate it if you could help me out: The question: Which compound's molecular formula is the same as its empirical formula: A. C2H5OHB. CH3CHOOHC. C6H6D. C8H18 I know its obviously not C or D, empirical formulae: CH and C4H9 but I dont know for the first two please help... Reply Link to post Share on other sites More sharing options...
Msj Chem Posted December 27, 2015 Report Share Posted December 27, 2015 (edited) The empirical formula is the lowest whole number ratio of atoms in a compound. In A, there is 2 C atoms, 6 H atoms and 1 O atom. This is already the lowest whole number ratio of atoms (if you divided the formula by 2, you would get half an O atom which is not a whole number). So this is the molecular formula and the empirical formula.In B, there are 2 C atoms, 4 H atoms and 2 O atoms. This can be divided by 2 to give CH2O, which is the lowest whole number ratio of atoms in the compound ( by the way there is mistake in the formula, it should be CH3COOH). Edited December 27, 2015 by Msj Chem 1 Reply Link to post Share on other sites More sharing options...
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