m.k.2015 Posted December 25, 2014 Report Share Posted December 25, 2014 Hi everybody, could any of you please explain why the potential difference across the burned out light bulb is 15 V? I am only struggling with this part of the question. Thanks in advance Reply Link to post Share on other sites More sharing options...
HiggsHunter Posted December 25, 2014 Report Share Posted December 25, 2014 Since bulb A is open circuit, the current in the circuit flows only through C and D in series. As these bulbs have equal resistance, the potential difference across C is half of 30v, i.e. 15v.Since there is no current through bulb B due to the open circuit in A, this 15v potential difference also appears across the bulb A. 1 Reply Link to post Share on other sites More sharing options...
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