m.k.2015 Posted December 22, 2014 Report Share Posted December 22, 2014 Hello everyone, can someone please help me by explaining the attached question. The answer is there, but I don't know how they got it Thankkkks Reply Link to post Share on other sites More sharing options...
Vioh Posted December 22, 2014 Report Share Posted December 22, 2014 (edited) Hello everyone, can someone please help me by explaining the attached question. The answer is there, but I don't know how they got it Thankkkks First of all, the solution in the picture that you posted is wrong due to typing error (i suppose) because and not . Apart from this typing error which leads to the wrong final answer, their method of solving is completely correct If you find this solution hard to understand, I suggest you use conservation of energy to solve this problem: At point 'a', the total energy of the particle is , where is the external energy, and is the potential at point 'a' At point 'b', the total energy of particle has now become , where is the kinetic energy of the particle, and is the potential at point 'b' Now, from conservation of energy we have: . Thus Plug in the given values, we have: which is also the right answer If there's anything unclear, feel free to ask Edited December 22, 2014 by Vioh 1 Reply Link to post Share on other sites More sharing options...
m.k.2015 Posted December 22, 2014 Author Report Share Posted December 22, 2014 Man honestly thank you so much .. I have a physics revision and this was just gonna make me give up haha .. thanks again Reply Link to post Share on other sites More sharing options...
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