Excluded Posted November 26, 2011 Report Share Posted November 26, 2011 My teacher haven't taught the class how to use the ratio test. I want to apply the ratio test for my math portfolio and unfortunately it's due on Monday, therefore I cannot ask my teacher how to use the ratio test. I would like to know if L = 0. So far I got up to here: I have no clue what I should do from here. Thank you in advance. Reply Link to post Share on other sites More sharing options...
kiwi.at.heart Posted November 26, 2011 Report Share Posted November 26, 2011 At this point you would sub in for n as n-->∞As n-->∞, n+1-->∞ so L-->0 Reply Link to post Share on other sites More sharing options...
rFumachi Posted November 26, 2011 Report Share Posted November 26, 2011 Why do you want to know if L = 0? It is enough to know that L is less than 1, to know that the series converges absolutely. What portfolio are you doing? 1 Reply Link to post Share on other sites More sharing options...
Excluded Posted November 26, 2011 Author Report Share Posted November 26, 2011 (edited) Why do you want to know if L = 0? It is enough to know that L is less than 1, to know that the series converges absolutely. What portfolio are you doing? I'm working on infinite summation [Edit] Another question... How is |1/(n+1)| = 0? Thanks in advance Edited November 26, 2011 by Excluded Reply Link to post Share on other sites More sharing options...
The Economist Posted November 26, 2011 Report Share Posted November 26, 2011 Why do you want to know if L = 0? It is enough to know that L is less than 1, to know that the series converges absolutely. What portfolio are you doing? I'm working on infinite summation [Edit] Another question... How is |1/(n+1)| = 0? Thanks in advance The lim of |1/(n+1)| as n tends to infinity is zero. 1 Reply Link to post Share on other sites More sharing options...
rFumachi Posted November 26, 2011 Report Share Posted November 26, 2011 (edited) When you divide 1 by a number that is increasingly larger (like infinity + 1), then the answer will be smaller, tending to zero. If you have any doubt graph it Edited November 26, 2011 by rFumachi 1 Reply Link to post Share on other sites More sharing options...
Excluded Posted November 27, 2011 Author Report Share Posted November 27, 2011 oh right, thanks~~ i was letting n= 0 thus 1/(0)+1 = 1 Although this is true, I just needed to let n continue to infinity. Reply Link to post Share on other sites More sharing options...
rFumachi Posted November 27, 2011 Report Share Posted November 27, 2011 oh right, thanks~~ i was letting n= 0 thus 1/(0)+1 = 1 Although this is true, I just needed to let n continue to infinity. You're welcome Self-studying series isn't that easy 1 Reply Link to post Share on other sites More sharing options...
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