Rigel Posted May 22, 2011 Report Share Posted May 22, 2011 Hello IBS, i was wondering about two things: What does the slope of a distance-time squared graph represent? Is this the actual acceleration or do i have to multiply it? And is it bad that my intercept with the y-axis is 8? Using: S = (at2)/2 Reply Link to post Share on other sites More sharing options...
Drake Glau Posted May 22, 2011 Report Share Posted May 22, 2011 (edited) d/t2=v/t because v=d/t So yes, your slope is your acceleration. Y intercept just means that when you started timing, or whoever starting timing they were already at a displacement of 8m or whatever unit. That point would be be 0,8 The slope of this graph (doing a derivative, assuming t2 is your x value so I'm just going to change it to x...) f(x)=ax/2 [(2a)-ax(0)]/22 2a/4 0.5a=slope. I'm hoping I didn't fail this part. I don't know I've got slope equaling a and 0.5a! This isn't working this late at night, I'm sorry if this further confuses you I'm going to say yes simply because a slope is y/x which is d/t2 which is v/t which is a... Edited May 22, 2011 by Drake Glau Reply Link to post Share on other sites More sharing options...
Rigel Posted May 22, 2011 Author Report Share Posted May 22, 2011 d/t2=v/t because v=d/t So yes, your slope is your acceleration. Y intercept just means that when you started timing, or whoever starting timing they were already at a displacement of 8m or whatever unit. That point would be be 0,8 The slope of this graph (doing a derivative, assuming t2 is your x value so I'm just going to change it to x...) f(x)=ax/2 [(2a)-ax(0)]/22 2a/4 0.5a=slope. I'm hoping I didn't fail this part. I don't know I've got slope equaling a and 0.5a! This isn't working this late at night, I'm sorry if this further confuses you I'm going to say yes simply because a slope is y/x which is d/t2 which is v/t which is a... Gotcha, but when we get the slope, do we have to multiply/divide by 2? Reply Link to post Share on other sites More sharing options...
Drake Glau Posted May 22, 2011 Report Share Posted May 22, 2011 according to the slope thingy I did you would multiply your slope by 2 O.o I think... Reply Link to post Share on other sites More sharing options...
Rigel Posted May 23, 2011 Author Report Share Posted May 23, 2011 according to the slope thingy I did you would multiply your slope by 2 O.o I think...Heh thanks much Alex! Reply Link to post Share on other sites More sharing options...
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