Recycle Bin Posted December 13, 2016 Report Share Posted December 13, 2016 Reply Link to post Share on other sites More sharing options...
IB_taking_over Posted December 13, 2016 Report Share Posted December 13, 2016 Basically, you set up an equation that starts with the known value, then the molar ratio from the reaction, and end up with the value you are solving for. My working is attached. (It's a much better explanation than the above words) 1 Reply Link to post Share on other sites More sharing options...
Msj Chem Posted December 13, 2016 Report Share Posted December 13, 2016 10.0 mol of C2H3Cl would require 25 mol of O2 to react completely because of the 2:5 molar ratio. 10.0 mol of O2 requires 4 mol of C2H3Cl to react and seeing as we have 10.0 mol, that makes O2 the limiting reactant. The ratio of the limiting reactant O2 to H2O is 5:2, therefore 10.0 mol of O2 will produce 4 mol of H2O. 2 Reply Link to post Share on other sites More sharing options...
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