Guest Posted January 15, 2016 Report Share Posted January 15, 2016 (edited) In the following reaction, what is equal to the rate of production of NO gas? 4NH3 + 5O2 -> 4NO + 6H2O The answer is "four-fifths the rate of disappearance of O2 gas. I don't understand why, please help! Edited January 15, 2016 by frank!e Reply Link to post Share on other sites More sharing options...
Msj Chem Posted January 15, 2016 Report Share Posted January 15, 2016 It's referring to the molar ratio of O2 to NO. 4 mol of NH3 react with 5 mol of O2 to form 4 mol of NO and 6 mol of H2O. So for every 5 mol of O2 that react with NH3, 4 mol of NO are produced. To be honest, that answer is quite confusing! Reply Link to post Share on other sites More sharing options...
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