iggy_gim Posted December 3, 2014 Report Share Posted December 3, 2014 Hey guys,So i am currently trying to figure a problem out that our teacher came up with. A brass weight whose mass is 200 g (0.2kg) is heated in a hot water bath on a hot plate. After heating for three minutes, it is transferred to a calorimeter filled with 175 grams (0.175 kg) of water. The calorimeter is left to sit and is measured five minutes later to have a net temperature change of 7 K. What is the specific heat of brass assuming that the calorimetric constant is 195 J K^-1 and the specific heat capacity of water is 4200 J K^-1 kg^-1. It seems to me it is missing the initial temperature of the boiling water/brass to find the temperature change of the brass. Am I correct in thinking this? Thanks Reply Link to post Share on other sites More sharing options...
Baller97 Posted December 4, 2014 Report Share Posted December 4, 2014 Hey guys,So i am currently trying to figure a problem out that our teacher came up with. A brass weight whose mass is 200 g (0.2kg) is heated in a hot water bath on a hot plate. After heating for three minutes, it is transferred to a calorimeter filled with 175 grams (0.175 kg) of water. The calorimeter is left to sit and is measured five minutes later to have a net temperature change of 7 K. What is the specific heat of brass assuming that the calorimetric constant is 195 J K^-1 and the specific heat capacity of water is 4200 J K^-1 kg^-1. It seems to me it is missing the initial temperature of the boiling water/brass to find the temperature change of the brass. Am I correct in thinking this? Thanks(Using the equation of q=mcdeltaT), q=0.2 x 4.2 x 7= 5.88 kJ mol^-1You don't need the initial temperature. Delta T means the change in temperature between the initial and final, so you should use that for delta T and you'll be good. Reply Link to post Share on other sites More sharing options...
Vioh Posted December 4, 2014 Report Share Posted December 4, 2014 (Using the equation of q=mcdeltaT), q=0.2 x 4.2 x 7= 5.88 kJ mol^-1You don't need the initial temperature. Delta T means the change in temperature between the initial and final, so you should use that for delta T and you'll be good. I don't really know what you are calculating here, but it's clear that you haven't gotten the result for the specific heat capacity of brass. Due to conservation of energy & due to the law of thermodynamics, the real equation should be:0.2 × cbrass × ΔTbrass = 0.175 × 4200 × 7 + 195 × 7 (where ΔTbrass≠7) Since there're 2 unknowns in the equation (cbrass and ΔTbrass), it's impossible to solve for the specific heat capacity of brass. Unless there's another method of approaching this question, I would agree with iggy_gim that: It seems to me it is missing the initial temperature of the boiling water/brass to find the temperature change of the brass. Am I correct in thinking this? Reply Link to post Share on other sites More sharing options...
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