Colin Posted February 6, 2011 Report Share Posted February 6, 2011 So i performed 3 trials of an experiment and i recorded the following data:17.12 cm +/- .1 cm, 17.73 cm +/- .1cm, 17.42 cm +/- .1 cmI need to take the average of this data, but I'm unsure of what to do with the uncertainties.. do you add the uncertainties together so my final average ends up to be 17.42 cm +/- .3 cm? Reply Link to post Share on other sites More sharing options...
Drake Glau Posted February 6, 2011 Report Share Posted February 6, 2011 What you do to the measurements is what you do to the uncertainty. Average them. Should be 17.42 (I'm trusting your math here) +/-0.1 Reply Link to post Share on other sites More sharing options...
Colin Posted February 7, 2011 Author Report Share Posted February 7, 2011 are you sure you wouldn't consider the uncertainties for all 3 trials? (+/-.3?) Reply Link to post Share on other sites More sharing options...
Ridamalik Posted February 7, 2011 Report Share Posted February 7, 2011 So i performed 3 trials of an experiment and i recorded the following data:17.12 cm +/- .1 cm, 17.73 cm +/- .1cm, 17.42 cm +/- .1 cmI need to take the average of this data, but I'm unsure of what to do with the uncertainties.. do you add the uncertainties together so my final average ends up to be 17.42 cm +/- .3 cm?You take the average of these trials, which is 17.42 and then you add the uncertainities, which is +/- 0.3 cm. Reply Link to post Share on other sites More sharing options...
darkwatch218 Posted March 13, 2011 Report Share Posted March 13, 2011 Drake Glau is correct, you would average the uncertainty so it becomes +/- 0.1cm Reply Link to post Share on other sites More sharing options...
Drake Glau Posted March 13, 2011 Report Share Posted March 13, 2011 Oh, you could also find the % uncertainty and average those and have your measure+/-% Reply Link to post Share on other sites More sharing options...
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