The Fish Posted October 19, 2010 Report Share Posted October 19, 2010 Hello!I am just beginning Physics 11 IB.I am having a bit of trouble with a question. Perhaps the answers in the back of my book are wrong (as they tend to be sometimes.) For those of you who have it, it is "Physics for the IB Diploma" by K. A. Tsokos. Page 86, #24.Two bodies are joined by a string and are pulled up an inclined plane that makes an angle of 30 degrees to the horizontal. So it is an inclined plane. At the bottom is a 8.0kg body, then a string connecting it to a 4.0kg body, and there is a force F on the 4.0kg body, all at an angle of 30 degrees.Calculate the tension of the string when:a.) the bodies move with constant speedThat is easy. The tension is mg sin30, since that is the parallel force of gravity on the 8.0kg body, so 80 sin30 = 40N.b.) The bodies move up the plane with an acceleration of 2.0 ms-2I thought it would be the same, but the back of the book says it is 56N. Where does this number come from?c.) What is the value of f in each case?I don't know how to find that either.Do YOU? Link to post Share on other sites More sharing options...
dessskris Posted October 19, 2010 Report Share Posted October 19, 2010 I have the same textbook and have finished this chapter.a) T=mg sin30b) T=mg sin30 + mac) case a) F=T + Mg sin30c) case b) F=T + Mg sin30 + Mam=8.0 kg and M=4.0 kg Link to post Share on other sites More sharing options...
dessskris Posted October 19, 2010 Report Share Posted October 19, 2010 Automatic generated messageThis topic has been closed by a moderator.Reason: question answeredIf you disagree with this action, please report this post, and a moderator or administrator will review it.Kind regards,IB Survival Staff Link to post Share on other sites More sharing options...
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