Destiny of Pi Posted October 16, 2017 Report Share Posted October 16, 2017 Hi guys, I am having trouble to figure out a way to solve the second part of this problem. If anyone could help, that would be great. The answer I got for part a is 10.3% Reply Link to post Share on other sites More sharing options...
kw0573 Posted October 16, 2017 Report Share Posted October 16, 2017 The key to the second part is to define a new binomial distribution X ~ B(100, answer from a), which is applicable when each apple can take on one of two values: too small, not too small. 1 Reply Link to post Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.