Tsaren Posted July 22, 2012 Report Share Posted July 22, 2012 Why does the volume and surface area decrease when the cell gets bigger? Shouldn't it increase? Thank you for respond! Reply Link to post Share on other sites More sharing options...
LMaxwell Posted July 22, 2012 Report Share Posted July 22, 2012 (edited) Hi,Take two cells, one has dimensions 1x1x1 (cell A) and the other has dimensions 3x3x3 (cell B).Cell A:Dimensions (mm): 1x1x1Surface area (mm2): 6Volume (mm3): 1Surface area to volume ratio: 6:1 = 6Cell B:Dimensions (mm): 3x3x3Surface area (mm2): 54Volume (mm3): 27Surface area to volume ratio: 54:27 = 2As you can see, cell A has a far greater surface area to volume ratio than cell B.Hope this explained the concept better,brof Edited July 22, 2012 by brofessional 2 Reply Link to post Share on other sites More sharing options...
GhoVinsen Posted July 26, 2012 Report Share Posted July 26, 2012 Another way to look at it, if we take Surface Area / Volume, that's gonna be x^2/x^3 (since area is squared and volume is cubed). Of course the denominator will grow faster since it's cubed and hence the ratio will be smaller and smaller 1 Reply Link to post Share on other sites More sharing options...
LeonardoHerrmann Posted March 1, 2021 Report Share Posted March 1, 2021 On 7/22/2012 at 12:47 PM, LMaxwell said: Hi, Take two cells, one has dimensions 1x1x1 (cell A) and the other has dimensions 3x3x3 (cell B). Cell A: Dimensions (mm): 1x1x1 Surface area (mm2😞 6 Volume (mm3😞 1 Surface area to volume ratio: 6:1 = 6 Cell B: Dimensions (mm): 3x3x3 Surface area (mm2😞 54 Volume (mm3😞 27 Surface area to volume ratio: 54:27 = 2 As you can see, cell A has a far greater surface area to volume ratio than cell B. Hope this explained the concept better, brof what is a possible experiment with surface to volume ratio like for my ia Reply Link to post Share on other sites More sharing options...
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