g_ar

Yea I agree, I ended up doing the CLOA extended response too. I did health psych and developmental psych options

Personally I didn't really find the psych HL exams very hard this year. They just asked questions straight off the syllabus, so if you leant the syllabus you'll be fine

Yep, I also agree, paper 1 was good, paper 2 was hard compared to other years and paper 3 was also good, but even paper 3 seemed a little more difficult than past papers.

haha yeahh i think a=2 is right.....yeahh hopefully, i have high hopes the grade boundaries will be lower for this year's maths papers

The base of the rectangle was 6-2x and the height was the function itself (I am not explaining why because I am assuming you correctly did the first part of the question based on what you said) The "second part" (certainly the question that was worth the most points I think) was giving the range of values "X" could take in order for the area of the rectangle to be increasing. You had to graph the function f(x)=base*height, which gave you a grade 3 function, clearly decreasing in a certain range. You just had to write the range of values for which the graph was decreasing did you get a=2 and b

i got 23.1 but i found the length by subtracting the circumference of the semi-circle with diameter 13.3 from the circumference of the whole circle with radius 7.

i definitely agree, i got enough sleep throughout the two years as well, never seemed to find getting enough sleep a problem. organization is the key to success in IB because the content is really not that difficult, there's just alot to get done in little time, n if u can manage that then youll be fine.

9gag.com

How did everyone find the psychology HL papers this year?

the discriminant only equals zero when the function has a repeated or double root. discriminant is >0 if there are two distinct real roots and discriminant <0 if there are no real roots.

doing heaps and heaps of internals is probably the worst part of ib....i'd rather study for exams

The discriminant of the function had to be = 0. I got that it could be any number except +2. It was something like (k-2)(k-2)=0 no, the discriminant had be >0, because the function has two distinct real roots.....so the answer is k>2

i got r=-2/3 and s=-27/5 as well

for Q.8 in section B of paper 2, for the last part, did anyone find the length of the arc by calculating the circumference of the whole circle than taking away the circumference of the semi- circle with diameter 13.3 from it?.......thats what i did, have no idea if its correct

yeahh i did that question, this is what i done not 100 % sure if its correct though......for part (a) the answer was 6-2x for part (b) which was finding an expression for the area of the rectangle..since op=x, the height of the triangle would be x substituted into the actual function......so the height of the rectangle is the actual function of the semi circle and the base is 6-2x